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标题: SQL中UNION 与 UNION ALL的区别分析 [打印本页]

作者: lanqiu    时间: 2009-1-20 09:22
标题: SQL中UNION 与 UNION ALL的区别分析
  UNION 运算符:      将两个或更多查询的结果组合为单个结果集,该结果集包含联合查询中的所有查询的全部行。这与使用联接组合两个表中的列不同。      使用 UNION 组合两个查询的结果集的两个基本规则是:      所有查询中的列数和列的顺序必须相同。      数据类型必须兼容。        这种多结果的查询组合为单一结果集在实际中应用的非常方便。但在应用中也有有着问题,如下实例可以进一步说明问题。      问题描述:        为了进一步分析与统计企业中关键部件的生产进度情况,采用了一个表Key_Item_Cal,其结构如图一:    

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  通过联合查询,将查询分为三个方面:      1、提出数据的基础明细,其代码如下:   SELECT dbo.Key_item.Key_item_name AS Item_Name,       dbo.H_MORVE.QTY_RECVD1 AS Quantity, dbo.Key_item.Style AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      Order by Style asc       

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  2、提出数据的一级汇总明细,其代码如下:   SELECT dbo.Key_item.Key_item_name AS Item_Name,       SUM(dbo.H_MORVE.QTY_RECVD1) AS Quantity,MAX(dbo.Key_item.Style) AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      GROUP BY dbo.Key_item.Style,dbo.Key_item.Key_item_name      order by Style      其结果如图如示:       

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  3、提出数据的二级汇总明细,其代码如下:   SELECT MAX(dbo.Key_item.Key_item_name) as Item_Name,      SUM(dbo.H_MORVE.QTY_RECVD1) as Quantity,       dbo.Key_item.Style as Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      GROUP BY dbo.Key_item.Style      ORDER BY dbo.Key_item.Style asc      其结果如图所示:       

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  总体的设计就如以上所示,但通过UNION联接的时候出现了新的问题。通过以下例子,就可以看出UNION与UNION ALL的区别      方案一,其代码如下:      SELECT dbo.Key_item.Key_item_name AS Item_Name,       dbo.H_MORVE.QTY_RECVD1 AS Quantity, dbo.Key_item.Style AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      UNION (      SELECT dbo.Key_item.Key_item_name AS Item_Name,       SUM(dbo.H_MORVE.QTY_RECVD1) AS Quantity,MAX(dbo.Key_item.Style) AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      GROUP BY dbo.Key_item.Style,dbo.Key_item.Key_item_name      UNION      SELECT MAX(dbo.Key_item.Key_item_name) as Item_Name, SUM(dbo.H_MORVE.QTY_RECVD1) as Quantity,       dbo.Key_item.Style as Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      GROUP BY dbo.Key_item.Style)      ORDER BY dbo.Key_item.Style asc      GO      其结果如下:       

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  问题:        通过以上结果,可以发现GR180.14.2.1后机架、PY165G.14.2.1B后机架和PY165K.14.2.1后机架的明细与其二级汇总值明显不符。而二级汇总的值是正确,为什么明细与汇总值不符?      针对这个问题,我采用了第二种方案。      方案二,其代码如下:      SELECT dbo.Key_item.Key_item_name AS Item_Name,       dbo.H_MORVE.QTY_RECVD1 AS Quantity, dbo.Key_item.Style AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      UNION ALL(      SELECT dbo.Key_item.Key_item_name AS Item_Name,       SUM(dbo.H_MORVE.QTY_RECVD1) AS Quantity,MAX(dbo.Key_item.Style) AS Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      WHERE (dbo.Key_item.Key_item 1)      GROUP BY dbo.Key_item.Style,dbo.Key_item.Key_item_name      UNION      SELECT MAX(dbo.Key_item.Key_item_name) as Item_Name,      SUM(dbo.H_MORVE.QTY_RECVD1) as Quantity,       dbo.Key_item.Style as Style      FROM dbo.Key_item LEFT OUTER JOIN       dbo.H_MORVE ON dbo.Key_item.Key_item = dbo.H_MORVE.ITEM      GROUP BY dbo.Key_item.Style)      ORDER BY dbo.Key_item.Style asc      GO      其结果如图:      

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  通过以上的例子,大家可以看出在UNION与UNION ALL在应用上区别 <




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